/* SPDX-License-Identifier: Apache-2.0
*
* The OpenSearch Contributors require contributions made to
* this file be licensed under the Apache-2.0 license or a
* compatible open source license.
*/
/*
* Modifications Copyright OpenSearch Contributors. See
* GitHub history for details.
*
*  Licensed to Elasticsearch B.V. under one or more contributor
*  license agreements. See the NOTICE file distributed with
*  this work for additional information regarding copyright
*  ownership. Elasticsearch B.V. licenses this file to you under
*  the Apache License, Version 2.0 (the "License"); you may
*  not use this file except in compliance with the License.
*  You may obtain a copy of the License at
*
* 	http://www.apache.org/licenses/LICENSE-2.0
*
*  Unless required by applicable law or agreed to in writing,
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*  "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
*  KIND, either express or implied.  See the License for the
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*/

using System;
using System.Collections.Concurrent;
using System.Collections.Generic;
using System.Diagnostics.CodeAnalysis;
using System.Linq;
using System.Threading;
using System.Threading.Tasks;
using OpenSearch.OpenSearch.Xunit.XunitPlumbing;
using OpenSearch.Net;
using FluentAssertions;
using Tests.Framework;
using static OpenSearch.Net.VirtualizedCluster.Rules.TimesHelper;
using static OpenSearch.Net.AuditEvent;

namespace Tests.ClientConcepts.ConnectionPooling.Sticky
{
	public class Sticky
	{
		/** Sticky Connection Pool
		 * Each connection pool returns the first `live` node so that it is sticky between requests
		*/
		[U]
		public void EachViewStartsAtNextPositionAndWrapsOver()
		{
			var numberOfNodes = 10;
			var uris = Enumerable.Range(9200, numberOfNodes).Select(p => new Uri("http://localhost:" + p));
			var pool = new StickyConnectionPool(uris);

			/**
			* Here we have setup a sticky connection pool seeded with 10 nodes.
			* So what order we expect? Imagine the following:
			*
			* Thread A calls `.CreateView()` and gets returned the first live node
			* Thread B calls `.CreateView()` and gets returned the same node, since the first
			* node is still good
			*/
			var startingPositions = Enumerable.Range(0, numberOfNodes)
				.Select(i => pool.CreateView().First())
				.Select(n => n.Uri.Port)
				.ToList();

			var expectedOrder = Enumerable.Repeat(9200, numberOfNodes);
			startingPositions.Should().ContainInOrder(expectedOrder);
		}

	}
}